A number of 50 digits has all its digits equal to 1 except the 26th digit. If the number is divisible by 13, then find the digit in the 26th place.

(In reply to

re: Re so easy by NK)

NK,

Take a number, say 652 . When you say its first digit is 6 second is 5 etc you count from left to right.

That's the way I did it. ( i did it my way..)

Of course you are free to define it the other way

and then X1=91 ===> X=9 .

So you and I solved two problems for the price of one.

enjoy, enjoy

ady