All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Calculation Mistake (Posted on 2003-11-19) Difficulty: 2 of 5
A boy was asked to calculate the arithmetic mean of ten positive integers each of which had 2 digits.
By mistake, he interchanged the two digits, a & b, in one of these ten integers. As a result, his answer for the arithmetic mean was 1.8 more than what it should have been.
Find the value of b-a.

See The Solution Submitted by Ravi Raja    
Rating: 2.2857 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Puzzle Solution Comment 8 of 8 |

Since there are ten numbers to begin with, it follows that by interchanging the digits,  the total must have been appreciated by  1.8*10 = 18.

(10b+a) - (10a+b) = 18, giving:
9(b-a) = 18, so that;
b-a = 2

Consequently, the required difference is 2.

Edited on October 16, 2007, 12:50 am
  Posted by K Sengupta on 2007-09-30 05:49:06

Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (1)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information