The sides of a triangle are in arithmetic progression and its area is 3/5th the area of an equilateral triangle with the same perimeter.
Find the ratio of the sides of the triangle.
(In reply to
re: arithmetic progression? by Tristan)
Just to get things started let us call the midlength side of our triangle 's', the short side 'sp' and the long side 's+p'. Then the perimeter is of course 3s and the area of the triangle is 3/5*(area of eqilateral = s2?3/4). The height of our triangle when side 's' is laid flat on the bottom is then s3?3/10. I am guessing we can solve for s and p with a little pythagorean algebra. Have Fun!
Edited on November 23, 2003, 7:13 pm

Posted by Eric
on 20031123 12:17:11 