The sides of a triangle are in arithmetic progression and its area is 3/5th the area of an equilateral triangle with the same perimeter.

Find the ratio of the sides of the triangle.

(In reply to re: arithmetic progression? by Tristan)

Just to get things started let us call the mid-length side of our triangle 's', the short side 's-p' and the long side 's+p'. Then the perimeter is of course 3s and the area of the triangle is 3/5*(area of eqilateral = s2?3/4). The height of our triangle when side 's' is laid flat on the bottom is then s3?3/10. I am guessing we can solve for s and p with a little pythagorean algebra. Have Fun!
Edited on November 23, 2003, 7:13 pm

Posted by Eric on 2003-11-23 12:17:11