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Prime Hopscotch (Posted on 2010-01-06) Difficulty: 4 of 5
Replace the numerals 1 through 8 with ever increasing prime numbers, always using the next lowest possible that is available1 to fulfill the criteria on the left. Then do the same for the right.

Present a series for the left, and one for the right.

7 + 8 = Square

6 = Prime

4 + 5 = Square


1 + 2 + 3 = Square


















7 + 8 = Cube

6 = Prime

4 + 5 = Cube


1 + 2 + 3 = Cube






If it was required that the Right set required "1" to be the next Prime following on after that used for the "8" in the Left set, what might the Right set read, if indeed it is possible?

1. Note, "always using the next lowest possible that is available" means that if it is next on the list it cannot be dismissed unless it is the last of a group of two or three and will not fulfill the criterion. Only then may you advance to the next.

See The Solution Submitted by brianjn    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: continuing on with the "square" version | Comment 14 of 17 |
(In reply to continuing on with the "square" version (spoilers for part 1) by Charlie)

Worth dropping a note to Neil Sloane?

Note that 17, 47, 71, 283, 881, 1913, within the range before being stopped, don't allow a continuation when used in square 1 as the start. Is there a pattern or rule that would specify this? Something to do with primes that are too close to one another to allow a third prime to add to form a square?

Could a pattern exist then such that;
  Sq          Sq    P    Sq       Sq      P  ...
P+P+P    P+P    P   P+P   P+P+P   P ....

I'm not totally serious about contacting Sloane, but .....

  Posted by brianjn on 2010-01-07 01:23:54

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