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Power Pattern Poser (Posted on 2010-04-27) Difficulty: 2 of 5
The cube of the next even positive integer is written beside the square of every odd positive integer in ascending order, without commas or spaces, resulting in this infinite pattern:

1896425216495128110001211728........

Determine the 2010th digit in the above pattern.

See The Solution Submitted by K Sengupta    
Rating: 1.0000 (1 votes)

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Answer. No time to explain. | Comment 1 of 3
There are many ways I may have erred, but here is what I found:

Digit number 2010 is a 7.

It is inside of 54^3 = 157646

  Posted by Jer on 2010-04-27 17:27:03
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