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Little cubes (Posted on 2010-02-27) Difficulty: 4 of 5
The difference of the cubes of two non-negative successive integers is a square of an integer. Find few possible pairs.
How about a general formula or evaluation algorithm for a(n)?

  Submitted by Ady TZIDON    
Rating: 4.0000 (2 votes)
Solution: (Hide)
Some couples (a,b) for (a+1)^3-a^3=b^2 :
(0, 1), (7, 13), (104, 181),...
To get more, use the recurrence relations :
a[n] = 14a[n-1] - a[n-2] + 6 and b[n] = 14b[n-1] - b[n-2]

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Solutionre: computer exploration -- Sloane back on-lineCharlie2010-03-01 03:02:49
Analytical findings (spoiler)Harry2010-02-27 21:14:12
Some Thoughtsre(2): computer explorationBrian Smith2010-02-27 18:51:49
re: computer explorationJim Keneipp2010-02-27 18:20:40
Some Thoughtscomputer explorationCharlie2010-02-27 14:29:40
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