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Sum (Pair Product) - Sum = 21 (Posted on 2010-06-07) Difficulty: 2 of 5
Determine all possible triplet(s) (a, b, c) of positive integers, with a ≤ b ≤ c, that satisfy this equation.

a*b+b*c+c*a - (a+b+c) = 21

No Solution Yet Submitted by K Sengupta    
Rating: 2.0000 (1 votes)

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Solution overkill solution | Comment 2 of 4 |

DEFDBL A-Z
FOR a = 1 TO 1000
FOR b = a TO 1000
FOR c = b TO 1000

 IF a * b + b * c + c * a - (a + b + c) = 21 THEN PRINT a; b; c

NEXT
NEXT
NEXT

finds

 1  1  22
 1  2  11
 2  2  7
 2  3  5

Overkill because lowest difference for given max number (c) should be when a and b are each 1. Then if

1+ c+c - (1+1+c) > 21

c > 22

and vice versa so we shouldn't expect any of the numbers to be greater than 22. 


  Posted by Charlie on 2010-06-07 13:19:11
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