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x^3 = y^2 – 15 (Posted on 2010-07-08) Difficulty: 3 of 5
Determine all possible pair(s) (x, y) of positive integers that satisfy the equation: x3 = y2 – 15

See The Solution Submitted by K Sengupta    
Rating: 3.3333 (3 votes)

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Start (and end?) | Comment 1 of 11

 x=1 and y=4 satisfies the equation.  Any others? 

EDIT -- 

There is also 109 ** 3 = 1295029 = 1138 ** 2 - 15

Some more exploring to do ...

Edited on July 8, 2010, 1:16 pm
  Posted by ed bottemiller on 2010-07-08 12:51:26

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