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x^3 = y^2 15 (Posted on 2010-07-08) Difficulty: 3 of 5
Determine all possible pair(s) (x, y) of positive integers that satisfy the equation: x3 = y2 15

No Solution Yet Submitted by K Sengupta    
Rating: 2.5000 (2 votes)

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Solution | Comment 2 of 11 |

Testing for solutions, (1,4) and (109, 1138) are the only pair of positive integers found that satisfy the equation.

Extending the solution into the imaginary numbers, the number pairs (-4, 7i) and (-4, -7i) will also satisfy the equation. All other numbers found that satisfy the equation are fractional.

 

Edited on July 8, 2010, 4:24 pm
  Posted by Dej Mar on 2010-07-08 13:35:16

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