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x^3 = y^2 15 (Posted on 2010-07-08) Difficulty: 3 of 5
Determine all possible pair(s) (x, y) of positive integers that satisfy the equation: x3 = y2 15

No Solution Yet Submitted by K Sengupta    
Rating: 2.5000 (2 votes)

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analytical start (dead end?) | Comment 7 of 11 |
It didn't lead to anything, but I subtracted 1 from each side and factored to reach:

(x-1)(x*x + x +1) = (y-4)(y+4)

  Posted by Steve Herman on 2010-07-09 13:56:50
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