Substitute each of the letters by a different digit from 0 to 9 to satisfy this system of alphametic equations. None of the numbers as well as none of the exponents contains a leading zero.
- (DID)W = FXA, and:
- (FLY)A = YLI, and:
- (LOW)O = ILT
It is solvable instantly, once you
write abc^k=d^mn in a form: