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Flying Low (Posted on 2010-08-05) Difficulty: 2 of 5
Substitute each of the letters by a different digit from 0 to 9 to satisfy this system of alphametic equations. None of the numbers as well as none of the exponents contains a leading zero.
  • (DID)W = FXA, and:
  • (FLY)A = YLI, and:
  • (LOW)O = ILT

No Solution Yet Submitted by K Sengupta    
Rating: 2.0000 (1 votes)

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Solution my way | Comment 3 of 5 |

It is solvable instantly, once you

write abc^k=d^mn in a form:





343=7^(18/6)  did

729=9^(24/8)  fly

256=4^(20/5)  low


  Posted by Ady TZIDON on 2010-08-05 12:18:30
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