Substitute each of the letters by a different digit from 0 to 9 to satisfy this system of alphametic equations. None of the numbers as well as none of the exponents contains a leading zero.
- (DID)W = FXA, and:
- (FLY)A = YLI, and:
- (LOW)O = ILT
(In reply to my way
by Ady TZIDON)
Nice approach, Ady! I found only the last (and shortest -- 13 digits) of the three. I suspect the system I was using did not allow enough significant digits internally to find the other two, but perhaps a coding error. I noticed that LOW (256) was a power of I (4), but didn't follow through to think of the reductions. The MS Calculator allows enough digits to check these out, if I had found them.
My initial reply regarding the interpretation was out of place, since the last sentence clearly intended the usual alphameric interpretation e.g. LT = 10*L + T (not L*T).