Substitute each of the capital letters in bold by a different base ten digit from 0 to 9 such that each of EEN, VIER and NEGEN is a perfect square. None of the numbers can contain any leading zero.

Disregarding the non leading zero condition, if we additionally impose the restriction that GIVEN is divisible by 23, then what will be the corresponding substitution?

EEN VIER NEGEN
441 3249 14641
21²  57²  121²

Given leading zeroes with GIVEN MOD 23 = 0
EEN VIER NEGEN GIVEN
004 2601 40804 86204
 2²  51²  202²  3748·23

Posted by Dej Mar on 2010-08-18 03:08:06