All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Back to the Wall (Posted on 2010-04-28) Difficulty: 3 of 5


No! Not a firing squad nor the need for a continuous line to cross all line segments just once!

To each vertex labeled A to L apply a different value from 1 to 12. Let V, W, X, Y and Z be the sums of their respective surrounding vertices.

Provide at least one example where V=W=X=Y=Z, or offer a reason why this, like the continuous line, is impossible.

See The Solution Submitted by brianjn    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re: If rectangle sums only of counters... | Comment 12 of 17 |
(In reply to If rectangle sums only of counters... by ed bottemiller)

When my original interpretation was used, having some of the polygons be pentagons (albeit with one 180° angle each), the common sum could be anywhere from 25 through 32.

When each is taken to be only a strict rectangle, with only four vertices, the common sum could be anywhere from 23 through 29, except not 26.


  Posted by Charlie on 2010-04-30 03:21:39
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (13)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information