All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Equilateral Right Angle Locus (Posted on 2010-10-25) Difficulty: 3 of 5
ABC is an equilateral triangle. M is a point inside triangle ABC and, the respective feet of perpendiculars from M to the sides BC, CA and AB are denoted by D, E and F.

Determine the locus of all such points M for which / FDE is a right angle.

No Solution Yet Submitted by K Sengupta    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
The easy way. Comment 2 of 2 |

1. Construct congruent triangle A'BC as a reflection of ABC across line BC.

2. The part of the circle with origin A' and radius A'C that lies inside ABC represents the required locus.

3. The 3-point circle intersecting B,M,C is equivalent.


  Posted by broll on 2010-10-25 16:17:35
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information