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Calendar Cubes pt 3 (Posted on 2003-04-06) Difficulty: 4 of 5
In the problem Calendar cubes you figured out the maximum amount of days you could fit on two cubes by putting numbers on both cubes and using the faces of the cubes to combine and make more numbers.
In Calendar cubes pt 2 You figured out how many months you could fit on two cubes.
Now in calendar cubes pt 3 you must figure out how many days of the year you can fit on two cubes. E.G one cube says mar(for march) and another says 5. so you could make the date march 5 and that would count as one date.

To represent months you may use
a) the first letter of that month
b) the first and second letter of that month
c) the first three letters of that months. So for january you could use either j, ja or jan to represent that month.
Also no two letters or letter combinations can represent the same month. So j cannot stand for june and july, but you can have j stand for june and ju stand for july. Also note that one month symbol (lets say au for august) can be on 1 face of 1 cube.

See The Solution Submitted by Alan    
Rating: 2.3000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Attempt at a solution (probably too naive) | Comment 2 of 14 |
On the face of it, it would seem the month cube could handle only 6 months of the year, as I can't see any way of representing one month as the upside down version of another or similar trick. The date cube could have 6 figures, but if one of the m is a 6 it could serve as a 9 also. So we'd have 7 dates in each of 6 months, for 42 dates within the year that could be represented.
  Posted by Charlie on 2003-04-06 16:28:35
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