In the problem Calendar cubes you figured out the maximum amount of days you could fit on two cubes by putting numbers on both cubes and using the faces of the cubes to combine and make more numbers.
In Calendar cubes pt 2 You figured out how many months you could fit on two cubes.
Now in calendar cubes pt 3 you must figure out how many days of the year you can fit on two cubes. E.G one cube says mar(for march) and another says 5. so you could make the date march 5 and that would count as one date.

To represent months you may use
a) the first letter of that month
b) the first and second letter of that month
c) the first three letters of that months. So for january you could use either j, ja or jan to represent that month.
Also no two letters or letter combinations can represent the same month. So j cannot stand for june and july, but you can have j stand for june and ju stand for july. Also note that one month symbol (lets say au for august) can be on 1 face of 1 cube.

There are two errors within the solution.

Firstly, you are using A to represent both April and August which is expressly forbidden in the rules. Since you created 11 numbers on the number cube then by losing a month your solution reduces by 11.

Secondly, at the end of the first paragraph you say "This gives us 8 months". Then in the middle of the second paragraph you say "Now we add 9 because only 9 of the months on the cube have 30 days". Since you only found 8 months your solution reduces by a further 1.

I make it that your solution gives 78 possibilities.

Posted by fwaff on 2003-04-14 03:38:29