All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Another Square (Posted on 2010-07-06) Difficulty: 4 of 5

No Solution Yet Submitted by brianjn    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Solution (as interpreted) | Comment 3 of 9 |
(In reply to re: Solution (as interpreted) by Charlie)

Charlie, Thanks for the clarification.  I think I would have a solution (perhaps not unique) if I changed my conversion of 64 (base 10) from 40 (base 16) to 22 (base 31), keeping the other four I had from bases 11,12,13,14).

If I am correct that there are five squares (16,36,49,64,100) then the lowest possible set of two-digit bases (11..15) would be 65, and the lowest "available" square would then be 81 (which is 11+12+13+14+31).  


  Posted by ed bottemiller on 2010-07-06 19:04:41
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information