(In reply to Solution
I don't think that is the same thing.
Praneeth's solution was to produce an F(n-2) using F(n) F(n-1)'s.
My question asked for production of an F(n) using F(n) F(n-1)'s.
So instead of making a 5 using 5 3's, Praneeth's solution (if I understand it correctly) would be to make a 2 using 5 3's. Even then, the 1st 4 3's can make the 2: 3/3 + 3/3, but then there's a pesky 3 leftover, not enough to make a zero, ie 3-3.
Posted by Larry
on 2010-07-09 21:19:06