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Equidistant points on the Axes (Posted on 2003-03-28) Difficulty: 2 of 5
Two points, A and B, are on the Cartesian plane at (-1,4) and (9,6).

A. What point on the x-axis is equidistant from each of these two points?

B. What point on the y-axis is equidistant from these two points?

See The Solution Submitted by Charlie    
Rating: 3.2000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution pretty easy | Comment 4 of 9 |
x-axis:
√6²+<9-x>²=√4²+<-1-x>²

solving gives --> x=5

y-axis:

√9²+<6-x>²=√-1²+<4-x>²

solving gives --> y=25

** Note: I can't get it to show up right on the screen but that Square root symbol encompasses each side of the equation. It's actually not needed (since it cancels out), but I through it in to clarify the structure (or at least attempt to). Thanks...
  Posted by DuCk on 2003-03-28 07:10:45
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