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Look for the pairs (
Posted on 20101015
)
Find the number of positive integer pairs (x; y) satisfying:
1/x+1/y=1/2010
Try to generalize for 1/n.
No Solution Yet
Submitted by
Ady TZIDON
Rating:
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(1 votes)
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No Subject
 Comment 2 of 3 
Well, xdog has done all the heavy lifting, except for a small typo.
2010 factors as 2*3*5*67. Answer is still 81.
In general,
(xn)(yn) = n^2,
so the number of satisfying pairs is just the number of divisors of n^2.
Edited on
October 15, 2010, 2:45 pm
Posted by
Steve Herman
on 20101015 14:41:30
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