C(UV) denotes the circle with diameter UV.
T(P,QR) denotes the tangential distance |PS|,
where point P lies outside C(QR), point S
lies on C(QR), and PS is tangent to C(QR).
Let A, B, C, and D be distinct, collinear
points in that order.
Construct a point E on line AD such that
|EF| = T(E,AB) = T(E,CD) = |EG|
Consider an x axis where A is at 0, and B,E,C, and D are at x values of B,E,C, and D.
With a little help from Pythagoras:
(E - B/2)^2 - (B/2)^2 = (C-E + (D-C)/2)^2 - ((D-C)/2)^2
Which leads to:
E = (D*C)/(D+C-B)
... although I think a compass and straight edge solution is what is being sought
Posted by Larry
on 2010-10-03 14:14:53