C(UV) denotes the circle with diameter UV.
T(P,QR) denotes the tangential distance PS,
where point P lies outside C(QR), point S
lies on C(QR), and PS is tangent to C(QR).
Let A, B, C, and D be distinct, collinear
points in that order.
Construct a point E on line AD such that
EF = T(E,AB) = T(E,CD) = EG
(In reply to
Algebraic solution by Larry)
Taking the algebraic solution, I solved for [CE] and [EB] to get an idea of the relative position of E between B and C.
Consider an x axis where A is at 0, and B,E,C, and D are at x values of B,E,C, and D.
E = (D*C)/(D+CB)
CE= ( C )* {(CB) / (D+CB)}
EB= (DB) * {(CB) / (D+CB)}
So, the ratio of the two line segments BE and EC is (DB)/C.
So for a geometric construction, draw any line "L1" (except horizontally) through C. Mark onto "line L1" point "M" which is distance C away from point C (the length C is the distance between A and C).
Now start from point "M", continue along line "L1" in the same direction and mark out the length DB and call it point "N". Now draw line "L2" from point N to point B. Draw line "L3", parallel to "L2" but passing through point M. Where line "L3" intersects line ABCD is going to be point E. By using similar triangles we have divided line segment BC into the proper ratio.
Edited on October 4, 2010, 10:36 pm

Posted by Larry
on 20101004 22:34:19 