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Numerator Divisibility Nuance (
Posted on 20110122
)
Each of p and q is a positive integer, with p and q being relatively prime, such that:
p/q = 1  1/2 + 1/3  1/4 + ......  1/1318 + 1/1319
Prove that p is divisible by 1979.
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Submitted by
K Sengupta
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Not obvious to me
 Comment 2 of 4 
Well, by combining adjacent pairs of terms, we can get
p/q = 1/2 + 1/12 + 1/30 + ...
or
1  1/6  1/20  1/42  ...
But I don't see how this helps. Hope somebody makes progress on the analytic front.
Posted by
Steve Herman
on 20110123 14:24:43
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