Suppose ABC is an equilateral triangle and P is a point inside the triangle, such that PA = 3 cms., PB = 4 cms., and PC = 5 cms.
Then find the length of the side of the equilateral triangle.

The area of an equilateral triangle  =.5 *a^2.9*sqrt(3).............(i)

The sum of three triangles APB, APC and BPC =.5*a*(3+4+5))...(ii)

Comparing (i) with (ii)    we get    a=4*sqrt(3)= 6.928

Posted by Ady TZIDON on 2014-10-18 11:13:43