perplexus.info :: Just Math : Diophantine quickie

Diophantine quickie (Posted on 2011-05-27)

Each of a, b, c, d and e is a positive integer satisfying this system of equations:

a^-2 + b^-2 + c^-2 = d^-2, and:

a+b+c = e²

Determine the smallest value of e. What are the next two smallest values of e?

See The Solution Submitted by K Sengupta

Rating: 5.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

The value of e

| Comment 2 of 3 |

e=2.71828182845904523536...

Posted by Math Man on 2011-05-27 18:46:47

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