Each of the small letters in bold represents a different base x digit from 0 to x1 to satisfy this alphametic equation. None of the numbers can contain any leading zero.
(x1)*number = integer
Determine the minimum positive integer value of x such that the above equation has at least one solution. What is the next smallest value of x having this property?
There are 9 letters used: numberitg so x is at least 9.
Since x is the base we can distribute (x1)*number = number0number = integer or
integer
+number
number0
r+r ends in 0 so either r is zero or it is half the base and this base must be even. If r is zero e+e ends in zero so e is half the base and the base must be even. [either way the base is even] If r is not zero, r+r has a carry so for e+e to end in r, r must be odd.
n=i+1
n+n gives a carry so n is at least half the base. I can't be half the base (e or r is) so it is at least one more than half the base and n is at least two more than half the base.
I probably will not be able to derive all that much more, but if nothing else this speeds up a computer search.

Posted by Jer
on 20110614 02:03:15 