Take the line segment whose endpoints are the points (1,0) and (-1,0) and a point of rotation (x,y).

If the segment is rotated all the way around the point it will trace out an annulus.

Find simplified formula for the area of this annulus in terms of x and y.

Redo this problem for a rectangle with corners at (1,1), (-1,1), (-1,-1), and (1,-1).

(In reply to part 1 spoiler by Charlie)

Negative of a negative on the y^2 is a positive, so:

|pi*(4*x + 2*y^2)|

Posted by Charlie on 2010-12-20 16:54:03