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Semiprime Switch (Posted on 2011-01-18) Difficulty: 3 of 5
Tom, Dick and Harry each chose two different 2-digit semiprime numbers (a semiprime is the product of exactly two different prime numbers). Any given semiprime may have been used by more than one of these characters, but any one person chose two different ones. In each of the three cases, the sum of the two semiprimes was a 3-digit semiprime.

Also, in each instance, if the units digits of the two semiprimes were swapped, to be paired with the other tens digit, the result was two semiprimes that were different from the original pair. Of course they added up to the same 3-digit semiprime as the first pair. In each of Tom's, Dick's and Harry's three semiprimes, none of the six primes from which they were made were the same: for example, if Tom's semiprimes were 93 and 94 adding up to 187, all six primes (3 and 31 for 93, 2 and 47 for 94 and 11 and 17 for 187) would all be different, satisfying this rule. The same was also true for each of the three people after the swap of units digits between the two 2-digit numbers.

Tom's, Dick's and Harry's 3-digit sums were all different, but Tom's and Harry's 3-digit sums did share a common prime factor, while Dick's did not.

What were Dick's numbers?
What were the other two sets of numbers?

  Submitted by Charlie    
Rating: 5.0000 (1 votes)
Solution: (Hide)
Here's a list of the pairs of 2-digit semiprimes that add up to a 3-digit semiprime, where none of the six primes involved in their makeup are the same.

In only three instances are such cases related where swapping the pairing of unit with tens places results in the same situation, and those are marked with asterisks.

Two of the cases involve the prime 2 in the 3-digit sum, and are therefore Tom's and Harry's. Dick's set is 35 and 94 (or 34 and 95) adding to 129.

 93      94      187
 91      94      185
 85      93      178
 87      91      178
 82      95      177
 86      91      177
 74      87      161
 74      85      159
 65      94      159
 77      82      159
 65      93      158
 69      86      155
 51      95      146 *        2*73
 55      91      146 *
 69      77      146
 51      94      145
 57      86      143
 58      85      143
 69      74      143
 55      87      142 *        2*71
 57      85      142 *
 51      91      142
 65      77      142
 55      86      141
 46      95      141
 39      95      134
 65      69      134
 57      77      134
 46      87      133
 39      94      133
 51      82      133
 35      94      129  *       3*43
 34      95      129  *
 38      91      129
 55      74      129
 38      85      123
 58      65      123
 46      77      123
 35      87      122
 57      65      122
 26      93      119
 33      86      119
 57      62      119
 33      85      118
 33      82      115
 57      58      115
 21      94      115
 38      77      115
 22      93      115
 26      85      111
 46      65      111
 34      77      111
 21      85      106
 15      91      106
 51      55      106

From Enigma No. 1618, "No common factors", by Richard England, New Scientist, 23 October 2010, page 28.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re(2): Problemhoodat2011-01-21 19:00:49
re: Problembrianjn2011-01-20 20:51:12
SolutionFrom the Spreadsheetbrianjn2011-01-20 20:38:57
Problemhoodat2011-01-20 16:23:13
Some ThoughtsTowards a Spreadsheetbrianjn2011-01-20 02:21:17
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