Just expanding on Charlies post trying to figure out the problem:
3D925B
pqrstuvw00000000000 is 25 hexadecimal digits which seems right. (1C)
_{16 }=(28)
_{10} In decimal 28! = 304888344611713860501504000000
Rather than convert this to hexadecimal lets just get an estimate of the size: log(304888344611713860501504000000)/log(16) ≈24.486 which indicates 25 digits. So far so good. 16^.486 ≈ 3.848 which also indicates a first digit of 3.
Now for the zeros at the end: Since 16 = 2^4 we only need to find the number of factors of 2 and divide by 4 to get the number of zeros. If the numbers 1 to 28, 14 are even, 7 are also multiples of 4, 3 are also multiples of 8, and 1 is a multiple of 16. 14+7+3+1 = 25. 25/4=6.25 which indicates the number in hexadecimal should end in 6 zeros, not the 11 shown.
It doesnt seem the problem is workable.

Posted by Jer
on 20110621 10:47:33 