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Product + Square = Difference of Squares (Posted on 2011-07-03) Difficulty: 3 of 5
Three positive integers P, Q and R, with P < Q < R, are in arithmetic sequence satisfying :
N*P*Q*R + Q2 = R2 - P2, where N is a positive integer.

Determine all possible quadruplet(s) (P, Q, R, N) that satisfy the above equation, and prove that no other quadruplet satisfies the given conditions.

  Submitted by K Sengupta    
Rating: 4.0000 (1 votes)
Solution: (Hide)
There is only a single quadruplet satisfying all the conditions of the problem.
It is given by (P, Q, R, N) = (1, 3, 5, 1).

For a detailed explanation, refer to the solution submitted by Harry in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionAnother approach (Spoiler)Harry2011-07-05 19:15:11
Possible solutionbroll2011-07-04 02:08:01
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