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Pythagoras Unconventional (Posted on 2011-02-10) Difficulty: 3 of 5

No Solution Yet Submitted by brianjn    
Rating: 4.0000 (1 votes)

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re: one possible choice | Comment 5 of 10 |
(In reply to one possible choice by Ady TZIDON)

Ady,
I see that you offer the digits 1, 2, 3 and 5 for the digits to compose six rods of length:
     1, √2, √3, 2, √5 and 3.

I have lifted and edited these values from my spreadsheet:              
    a   b  c       a     b      c      
    1    2    3        1    √2   √3      
    1    3    4        1    √3     2      
    1    4    5        1     2    √5      
    2    3    5       √2   √3   √5    

From your comment above you have indicated 5 Pythagorean triples, please, which one have I missed?

Incidentally, whilst looking at Daniel's offering I am reminded that Broll presented the length 2√2 as an interpretation of the then wording "exactly one digit". 

Looking back at his first comment he has followed the rules which I had defined but then I see Daniel has managed to interpret "using exactly one instance of a digit" in exactly the same vein (or that is my impression).

My intention was that just one solitary digit was to appear in any length attribute.

OH, how to word?

Edited on February 11, 2011, 8:16 am
  Posted by brianjn on 2011-02-11 02:02:36

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