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 Painter's Dilemma (Posted on 2011-03-08)
A painter desires to paint the 4 walls of a rectangular shaped room. Each wall has 100 sq. ft. of paintable surface, and a gallon of paint will cover 250 sq. ft. He has two full 1 gallon cans of paint. As he is ready to start, he realizes that one of the gallons of paint has 6% more pigment than the other. Since the paint store is closed and he wants to finish right away, he decides to mix the paint together. Alas, he has no additional containers to assist with the mixing, and no measuring device. However he is a good judge of surface area, and can accurately estimate the percentage of a given wall he has painted to any proportion.

Being an expert, he knows that the paint on any one wall must have exactly the same amount of pigment throughout, but adjacent walls can differ by up to 2% and not be noticed.

What is the step by step plan that the painter can use that satisfies the conditions and also minimizes the volume of paint transferred during mixing?

BONUS: What if the initial difference in pigment is 10%?

 No Solution Yet Submitted by Kenny M No Rating

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(In reply to Hint by Kenny M)

I loved this puzzle!

Solution:

Let P be the percentage of pigment in can #1.
Begin with can #1 containing 1 gallon with P% pigment,
and can #2 containing 1 gallon with P+6% pigment.
Paint the north wall from can #1, leaving 3/5 gallon with P% pigment.
Pour from can #2 into can #1 until can #1 is full,
leaving can #1 with 1 gallon with P+2.4% (3/5*P%+2/5*(P+6%)) pigment,
and can #2 with 3/5 gallon with P+6% pigment.
Paint the north wall from can #1 having P+2.4% pigment,
leaving can #1 with 3/5 gallon with P+2.4% pigment.
Pour from can #2 into can #1 until can #1 is full,
leaving can #1 with 1 gallon with P+3.84% (3/5*(P+2.4%)+2/5*(P+6%)) pigment,
and can #2 with 1/5 gallon with P+6% pigment.
Paint the west wall from can #1 having P+3.84% pigment,
leaving can #1 with 3/5 gallon with P+3.84% pigment,
and can #2 with 1/5 gallon with P+6% pigment.
Pour the remaining 1/5 gallon of can #2 into can #1,
leaving can #1 with 4/5 gallon with P+4.38% (3/5*(P+3.84%)+1/5*(P+6%)) pigment.
Paint the east and south walls from can #1.

The north wall is now painted with P+2.4% pigment;
the west wall with P+3.84% pigment;
and the east and south walls with P+4.38% pigment.

Bonus answer: replace the first 2 "paint" and "pour" steps above with:
Paint the north wall from can #2.
Pour from can #1 into can #2 until can #2 is full. Mix can #2 completely.
Pour from can #2 into can #1 until can #1 is full.
 Posted by Grant Stevens on 2011-04-02 19:03:17

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