All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Back to the base (Posted on 2011-03-30) Difficulty: 3 of 5
A certain 10-base integer with distinct digits can be converted to base b by merely reversing its digits.
Find the lowest value of b.

See The Solution Submitted by Ady TZIDON    
Rating: 3.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Derivation Comment 3 of 3 |
Let 10x+y be a two digit base 10 number where x<b and y<b.

It is to be equal to its reversal in base b: by+x

9x = (b-1)y
We want b to be as small as possible.
b cannot equal 2 because that would require x=1 and y=9, which violates y<b.  (91 is not proper in base 2, although in a sense it is 19 in base 10.)
For b to equal 3, again we would require x=2 and y=9.
It turns out b=4 is possible with x=1 and y=3 (there are other false solutions.)
So we have the reversal 13 (base 10) equals 31 (base 4.)

This is the smallest possible two digit solution, now to show there aren't smaller bases with more digits.

A base 2 solution is not possible, as the problem requires distinct digits and there are only two binary digits.

A base 3 solution would only be feasible with three digits.   With a 2 or 1 in the 10^2 place, the reversal can only be 1 or 2 times 3^2 plus 0 times 3 plus 2 or 1 which is no where near big enough.  So we are done.

  Posted by Jer on 2011-03-30 22:39:18
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information