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Almost equal (Posted on 2011-04-01) Difficulty: 1 of 5
Integers equal to each other or differing by 1 will be called "almost equal " within the contents of this problem.

In how many ways can 2011 be expressed as a sum of almost equal addends?
The order of the addends in the expression is immaterial.

See The Solution Submitted by Ady TZIDON    
Rating: 3.7500 (4 votes)

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April Fool's answer | Comment 1 of 10
Well, clearly it is infinite.  Among the number of infinite ways are:

2011 1's
2011 1's and 1 zero
2011 1's and 2 zeroes
2011 1's and 3 zeroes
2011 1's and 4 zeroes
2011 1's and 5 zeroes
2011 1's and 6 zeroes
2011 1's and 7 zeroes
2011 1's and 8 zeroes

etc.

  Posted by Steve Herman on 2011-04-01 12:27:43
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