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Almost equal (Posted on 2011-04-01) Difficulty: 1 of 5
Integers equal to each other or differing by 1 will be called "almost equal " within the contents of this problem.

In how many ways can 2011 be expressed as a sum of almost equal addends?
The order of the addends in the expression is immaterial.

See The Solution Submitted by Ady TZIDON    
Rating: 3.7500 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Bravo! Comment 10 of 10 |
Nice solution, Jer.
Nice puzzle, Ady!

  Posted by Steve Herman on 2011-04-02 14:02:58
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