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Another Quickie (Posted on 2011-03-13) Difficulty: 2 of 5
Let n and a be positive integers such that 3n^2=4a-1.

Prove that a is a difference of consecutive cubes.

See The Solution Submitted by broll    
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re: spoiler Comment 2 of 2 |
(In reply to spoiler by Ady TZIDON)

Nice, Ady!

Now can you use this result to produce a different method to solve 'short and sweet' (2011-02-21)?

  Posted by broll on 2011-03-14 01:43:19
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