Call 41/14 f(b), b denoting the base.
Since minimal value for b is 5 and f(5)=21/9=7/3>2
and lim f(b) is clearly 4 as b increases to infinity,
the integer must be 3.
Solving (4*b+1)/(b+4)=3 we get:
CHECK: DECIMAL VALUES 45/15=3
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