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 Domino Polygons (Posted on 2011-03-14)
Randomly draw three from a standard set of 28 Double Six Dominoes.

What is the probability they can be arranged in a triangle with each end touching another end with an equal number of spots?
For example: [1|3][3|0][0|1] can form such a triangle.
(Note: this triangle is not a legal configuration in an actual game of dominoes.)

What is the probability of being able to form a square in the same fashion?

How about 5? 6? 27? 26?

There doesn't seem to be a general formula. Is there?

 No Solution Yet Submitted by Jer No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 25! (Eureka!) | Comment 3 of 5 |
25 randomly drawn can form a 25-gon only if the undrawn three are all doubles, or if they form a triangle.

Probability that they are all doubles = 7/28 * 6/27 * 5/26 = 5/468

Probability that they form a triangle was previously calculated as 5/468.

Is this a coincidence, or a deep pattern?

I don't know, but they are mutually exclusive, so a 25-gon can be formed with probability 5/468 + 5/468 = 5/234

 Posted by Steve Herman on 2011-03-15 14:57:50

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