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Squaring Up The Digits II (Posted on 20110903) 

Determine all possible values of a base ten positive integer N such that N is precisely one
more than the sum of the squares of its digits.
No Solution Yet

Submitted by K Sengupta

Rating: 4.3333 (3 votes)


Possible soution

 Comment 4 of 7 

a^2+b^2+1=10a+b 4(a5)^2+(2b1)^2 = 97 say, (2x)^2+y^2=97 x=+/2, y=+/9 a5=2,a5=2 a={7,3} 2b1=9, (2b1=9) b={5} N={35,75}

Posted by broll
on 20110904 01:29:59 


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