All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Square Your Age (Posted on 2003-04-15) Difficulty: 2 of 5
The other day, Jim excitedly told me, "Did you realise I will turn x years old in the year x^2?"

He wasn't the first to think of this. The 19th century mathematician August de Morgan used to used to boast that he was x years old in the year x^2. He died in 1871.

In what year was Jim born? When will his prediction be true? In what year was de Morgan born? What is x in each case?

See The Solution Submitted by pleasance    
Rating: 2.7500 (8 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution First Possibility | Comment 3 of 20 |
We can calculate and see that:
(42)^2 = 1764, (43)^2 = 1849, (44)^2 = 1936 and (45)^2 = 2025.
So, it is obvious that 43 years old in the Year 1849, which implies that he was born in the year 1806, whereas Jim will turn 45 years in the year 2025 implying he was born in the year 1980.

So, in AUGUSTUS DE MORGAN's case, x = 43 and in JIM's case, x = 45. This was the first possibility.
  Posted by Ravi Raja on 2003-04-15 21:32:27
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (14)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information