Replace the interrogation marks in the following statements by appropriate digits (0 to 9) to make these statements valid:
D1: 34?561? is exactly divisible by 45
D2: 68??37 is exactly divisible by 99
D3: 9???057 is equal to 417 times ?1???
D3: 70??34? is exactly divisible by 792
D4: 4?18? is exactly divisible by 101
D5: 6?80?8??51 is exactly divisible by 73*137
For 34?561? to be divisible by 45 = 5*9, its digits must sum to a multiple of 9 and it must end in 0 or 5. The given digits sum to 19 so the unknown digits give 8 more. There are two possibilities (8,0) and (3,5). So the number is either 3485610 or 3435615.
For 68??37 to be divisible by 99 = 9*11 its digits must sum to a multiple of 9 and it has to meet the divisibility rule for 11. The given digits sum to 24 so the unknown digits give 3 or 12 more. The digits in the odd places sum to 6 more than the even places; this differential has to be brought down by 6 to 0 or up by 5 to 11. Digits summing to 3 cant do this, digits summing to 12 can only differ by an even amount. In this case 93=6 is what we want. So the number is 689337.
4?18? is also very easy (D2) if you set up a long multiplication:
abc
x 101
abc
abc
4?18?
b must be 8, a+c carries to make the first ?=9, then a=4, so c=7 as is the second ?. So the number is 49187

Posted by Jer
on 20110606 15:07:01 