The game of craps is played by rolling a pair of dice. If the total comes out to 7 or 11, the shooter wins immediately. If it comes out to 2, 3, or 12, the shooter loses immediately. If any other total shows on the first roll, the player continues to roll until either his original total comes up again, in which case he wins, or a 7 comes up, in which case he loses.

What is the probability the shooter will win?

(In reply to True Solution (Flaw in common answer.) by Joshua)

Are you saying you might be able to quit before pass or no-pass occurs?

Or are you saying something to do with how many times you play out the full game of multiple tosses? If that's the case, the original 49.2929… % doesn't change, as each game (multiple tosses) is independent.

Posted by Charlie on 2011-09-03 15:42:02