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As easy as abc (Posted on 2011-06-28) Difficulty: 3 of 5
Given an equation ax^2+bx+c=0 what values a,b cause the roots of the equation to be a and b and the discriminant to be equal to c?

No Solution Yet Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

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Three equations | Comment 2 of 10 |
Well yes, if the roots are a and b, then (x-a)(x-b) = 0

Multiplying by a gives
      ax2 -a(a+b)x +a2b = 0

Comparing the two equations, gives
(1)  b = -a(a+b)  which leads to b = -a2/(a+1), just as Dej Mar says

(2) c = a2

(3) c = the discriminant = b-4ac 

Solving (1), (2), and (3) should lead to discrete a, b and c values which constitute the solution

  Posted by Steve Herman on 2011-06-29 15:52:33
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