All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
As easy as abc (Posted on 2011-06-28) Difficulty: 3 of 5
Given an equation ax^2+bx+c=0 what values a,b cause the roots of the equation to be a and b and the discriminant to be equal to c?

No Solution Yet Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Three equations | Comment 2 of 10 |
Well yes, if the roots are a and b, then (x-a)(x-b) = 0

Multiplying by a gives
      ax2 -a(a+b)x +a2b = 0

Comparing the two equations, gives
(1)  b = -a(a+b)  which leads to b = -a2/(a+1), just as Dej Mar says

Also, 
(2) c = a2

and 
(3) c = the discriminant = b-4ac 

Solving (1), (2), and (3) should lead to discrete a, b and c values which constitute the solution

  Posted by Steve Herman on 2011-06-29 15:52:33
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (7)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information