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As easy as abc (Posted on 2011-06-28) Difficulty: 3 of 5
Given an equation ax^2+bx+c=0 what values a,b cause the roots of the equation to be a and b and the discriminant to be equal to c?

No Solution Yet Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

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re(2): a root of the matter ..???... | Comment 9 of 10 |
(In reply to re: a root of the matter ..???... by Ady TZIDON)

The problem does not ask us what value is c, yet here was the solution I was able to derive [with Q = SQRT(7)]:
(a, b, c) = {
(0, 0, 0),
([-5 + iQ]/8, [1 + 3iQ]/8, [57 + 11iQ]/128),
([-5 - iQ]/8, [5 +  iQ]/8, [ 5 + 17iQ]/128)
 }

Edited on July 2, 2011, 12:28 am
  Posted by Dej Mar on 2011-07-02 00:23:13

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