It turns out that the common logarithms of each of the numbers from 2 through 9 can be very well approximated by rational numbers of the form n/40.
Derive each of the numerators with no calculation aids beyond pencil and paper.
(In reply to re: Who is right for 7?....DETAILS
by Ady TZIDON)
Did you compute those powers by hand, using pencil and paper? That seems like a lot of work.
I personally would use the approach you mention to compute log(7), that is 4log(7)=log(2401) is about log(2400)=3log(2)+log(3)+2
Posted by Gamer
on 2011-06-02 05:11:42