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Fortieth logs (Posted on 2011-05-31) Difficulty: 2 of 5
It turns out that the common logarithms of each of the numbers from 2 through 9 can be very well approximated by rational numbers of the form n/40.

Derive each of the numerators with no calculation aids beyond pencil and paper.

See The Solution Submitted by Jer    
Rating: 4.5000 (2 votes)

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re(2): Who is right for 7?....DETAILS | Comment 14 of 15 |
(In reply to re: Who is right for 7?....DETAILS by Ady TZIDON)

Did you compute those powers by hand, using pencil and paper? That seems like a lot of work.

I personally would use the approach you mention to compute log(7), that is 4log(7)=log(2401) is about log(2400)=3log(2)+log(3)+2

  Posted by Gamer on 2011-06-02 05:11:42

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