All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Last three digits (Posted on 2011-10-19) Difficulty: 3 of 5
N is the product of all the prime numbers less than 100.

Determine the last three digits of N.

*** For an extra challenge, solve this puzzle without the aid of a computer program.

No Solution Yet Submitted by K Sengupta    
Rating: 3.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): two-thirds of a solution. | Comment 5 of 9 |
(In reply to re: two-thirds of a solution. by Matt)

It doesnt work this way.  Consider multiplying 2 two-digit numbers.  The digit in the tens place is the sum of two products plus any carries.

That third-from-the-end zero is the sum of many sub-products, not just the product of 2 and 5.

  Posted by Jer on 2011-10-19 13:57:49

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information