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1st+2nd=3rd (Posted on 2011-09-14) Difficulty: 3 of 5
If we place 192 in the 1st row, 384 in the second row and 576 in the 3rd row, then we get a 3x3 square, exhausting all non-zero digits.
In this square 1st row + 2nd row = 3rd row.

Please provide all other arrangements, satisfying this condition.

See The Solution Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

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Some Thoughts Mod 9 analysis Comment 3 of 3 |
By the way:

The 3rd row must be a multiple of 9.

Let a = first row, b = 2nd row, c = 3rd row.

By casting out 9's,
a +  b + c = 0 (mod 9)  (because all digits are there exactly once)

Also, a + b - c = 0  (initial problem)

Subtracting the two equations, we get
  2c = 0 mod 9,

So c = 0 mod 9

  Posted by Steve Herman on 2011-09-15 10:00:53
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