Without performing the actual division, determine whether 11298969 (base ten) is divisible by 2013 (base ten).
(In reply to
Hmm by Jer)
good work, for a divisibility rule for 61 see this wiki:
http://en.wikipedia.org/wiki/Divisibility_rule
pretty much, what you do is you take the last digit, multiply by 6, subtract from the rest (concactenanted), and repeat, if you reach zero, it is divisible, thus for our example we get
11298969
11298966*9=1129842
1129846*2=112972
112976*2=11285
11286*5=1098
1096*8=61
616*1=0
thus it is divisible

Posted by Daniel
on 20111130 09:45:12 