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Home > Logic > Weights and Scales
Pearls (Posted on 2002-05-23) Difficulty: 3 of 5
You have nine pearls, one of which is (as is usually the case in these problems) fake. You know that the fake pearl weighs less than the others, but it is (of course) impossible to distinguish from the others in any other way.

What is the minimum number of weighings that must be performed to find the fake pearl? How would you go about it?

  Submitted by levik    
Rating: 2.7143 (7 votes)
Solution: (Hide)
Divide the pearls into three groups: pearls A:(1,2,3) B:(4,5,6) and C:(7,8,9).

First, weigh the three pearls of A against the three pearls of B. If one of them weighs less than the other, then the fake pearl is in that group. Otherwise, it's in group C.

Having determined which group the pearls are in, take two pearls of that group, and weigh them. If one is lighter, then that one is fake. If they are both the same weight, then the fake one is the one you didn't put on the scale.

Thus we can determine the fake pearl in only two weighings.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Solution for any PEric2005-11-29 23:21:44
SolutionSOLUTION FOR P=15K Sengupta2005-11-19 00:33:47
re: SolutionJason Taylor2005-08-20 11:39:55
answervije2004-07-02 14:55:03
SolutionJenny Turner2004-06-02 17:29:13
SolutionSolutionAndrwe Mitchell2003-07-26 09:18:54
Solutionof courseJonathan Waltz2003-03-28 06:38:16
SolutionEasyTomM2002-05-23 13:22:50
Solutionfriedlinguini2002-05-23 11:42:52
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